X=-16x^2+96x+112

Solution for X=-16x^2+96x+112 equation:

X=-16X^2+96X+112

We move all terms to the left:

X-(-16X^2+96X+112)=0

We get rid of parentheses

16X^2-96X+X-112=0

We add all the numbers together, and all the variables

16X^2-95X-112=0

a = 16; b = -95; c = -112;
Δ = b2-4ac
Δ = -952-4·16·(-112)
Δ = 16193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-\sqrt{16193}}{2*16}=\frac{95-\sqrt{16193}}{32}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+\sqrt{16193}}{2*16}=\frac{95+\sqrt{16193}}{32}
$